求平方根的编程方法有多种,以下是一些常见的方法及其在Python、C语言和Java中的实现示例:
使用数学库函数
Python:可以使用`math.sqrt()`函数来计算平方根。
```python
import math
result = math.sqrt(16)
print(result) 输出 4.0
```
C语言:可以使用`sqrt()`函数,需要包含`math.h`头文件。
```c
include include int main() { double number = 16.0; double result = sqrt(number); printf("The square root of %.2f is %.2f ", number, result); return 0; } ``` Java:可以使用`Math.sqrt()`方法。 ```java public class Test01 { public static void main(String[] args) { double a = 16; System.out.println("16的平方根是" + Math.sqrt(a)); } } ``` Python: ```python def sqrt(n): x = n / 2 while True: y = (x + n / x) / 2 if abs(x - y) < 0.00001: 精度要求 return y x = y ``` C语言: ```c include double sqrt(double n) { double x = n / 2; while (1) { double y = (x + n / x) / 2; if (abs(x - y) < 0.00001) { return y; } x = y; } } int main() { double number = 16.0; double result = sqrt(number); printf("The square root of %.2f is %.2f ", number, result); return 0; } ``` Java: ```java public class Test01 { public static double sqrt(double n) { double x = n / 2; while (true) { double y = (x + n / x) / 2; if (Math.abs(x - y) < 0.00001) { return y; } x = y; } } public static void main(String[] args) { double a = 16; System.out.println("16的平方根是" + sqrt(a)); } } ``` Python: ```python def sqrt(n): if n < 0: raise ValueError("Cannot calculate square root of negative number.") left, right = 0, n while right - left > 0.00001: mid = (left + right) / 2 if mid * mid < n: left = mid else: right = mid return left ``` C语言: ```c include double sqrt(double n) { if (n < 0) { fprintf(stderr, "Cannot calculate square root of negative number. "); exit(1); } double left = 0, right = n; while (right - left > 0.00001) { double mid = (left + right) / 2; if (mid * mid < n) { left = mid; } else { right = mid; } } return left; } int main() { double number = 16.0; double result = sqrt(number); printf("The square root of %.2f is %.2f ", number, result); return 0; } ``` Java:牛顿迭代法
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